Question:

What is the half-life of a zero order reaction that takes 25 minutes for 80% completion?

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In Zero Order, the reaction proceeds at a steady pace. Half-life is proportional to initial concentration.
Updated On: May 13, 2026
  • 150.25 seconds
  • 937.50 seconds
  • 950.50 seconds
  • 156.25 seconds
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The Correct Option is B

Solution and Explanation


Step 1: Concept

For a zero-order reaction, the rate is constant, so $x = kt$ (where $x$ is amount reacted).

Step 2: Meaning

80% completion in 25 min means $0.8[A]_0 = k \times 25$. This gives $k = 0.8[A]_0 / 25$.

Step 3: Analysis

The half-life ($t_{1/2}$) for zero order is $[A]_0 / 2k$. Substituting $k$: $t_{1/2} = [A]_0 / (2 \times 0.8[A]_0 / 25) = 25 / 1.6 = 15.625$ minutes.

Step 4: Conclusion

Convert to seconds: $15.625 \times 60 = 937.5$ seconds. Final Answer: (B)
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