Question:

What is the atomic mass of Fe?
Given abundance of \[ {}^{54}_{26}Fe = 10\% \] \[ {}^{56}_{26}Fe = 85\% \] \[ {}^{57}_{26}Fe = 5\% \]

Show Hint

Average atomic mass is always calculated using weighted mean: \[ \frac{\sum (\text{mass}\times \text{abundance})}{100} \]
Updated On: Jun 25, 2026
  • \(55.65\)
  • \(55.75\)
  • \(55.85\)
  • \(55.95\)
Show Solution
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The Correct Option is C

Solution and Explanation

Step 1: Use formula for average atomic mass.
Atomic mass is calculated using weighted average: \[ \text{Atomic mass} = \frac{\sum (\text{isotopic mass}\times \text{percentage abundance})}{100} \]

Step 2: Substitute the given values.
\[ \text{Atomic mass of Fe} = \frac{(54\times10)+(56\times85)+(57\times5)}{100} \]

Step 3: Calculate each contribution.
\[ 54\times10=540 \] \[ 56\times85=4760 \] \[ 57\times5=285 \] Adding, \[ 540+4760+285=5585 \]

Step 4: Find the average atomic mass.
\[ \text{Atomic mass} = \frac{5585}{100} \] \[ =55.85 \]

Step 5: Final conclusion.
Hence, the atomic mass of Fe is \[ \boxed{55.85} \]
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