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what is oxidation state of xenon in xenonmonooxyte
Question:
What is oxidation state of xenon in xenonmonooxytetrafluoride?
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Xenon usually exhibits even oxidation states: +2, +4, +6, +8.
MHT CET - 2025
MHT CET
Updated On:
Jun 19, 2026
+2
+4
+6
+8
Show Solution
Verified By Collegedunia
The Correct Option is
C
Solution and Explanation
Step 1: Formula
Xenonmonooxytetrafluoride is $XeOF_{4}$.
Step 2: Analysis
Let oxidation state of $Xe$ be $x$. - $O = -2$ - $F = -1$ - Sum = 0
Step 3: Calculation
- $x + (-2) + 4(-1) = 0$ - $x - 2 - 4 = 0$ - $x = +6$
Step 4: Conclusion
Hence, the oxidation state is +6.
Final Answer:
(C)
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