Question:

What does $R_a$ indicate in the voltage equation $V=E_{b}+I_{a}R_{a}$ of DC motor?}

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The armature winding has a very low resistance ($R_a < 1\,\Omega$) to minimize $I_a^2 R_a$ copper losses and voltage drops. Under starting conditions, since back emf $E_b \propto N$ (speed) is zero, starter resistors are used to limit the starting current $I_s = V / R_a$.
Updated On: Jun 18, 2026
  • Input voltage
  • Back emf
  • Armature current
  • Armature resistance
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The Correct Option is D

Solution and Explanation



Step 1: Understanding the DC Motor Voltage Equation:

The fundamental voltage balance equation of a DC motor is given by: $$V = E_b + I_a R_a$$

Step 2: Identifying the Mathematical Terms:

Let us define each mathematical term within this electrical equation:
  • $V$: The terminal input DC voltage applied across the motor terminals (measured in Volts).
  • $E_b$: The Counter-Electromotive Force or Back emf induced in the armature conductor as it rotates in the magnetic field (measured in Volts). It is given by $E_b = \frac{\Phi Z N P}{60 A}$.
  • $I_a$: The current flowing through the armature conductors, known as the Armature Current (measured in Amperes).
  • $R_a$: The electrical resistance offered by the copper conductors of the armature winding, called the Armature Resistance (measured in Ohms, $\Omega$).
  • $I_a R_a$: The total resistive voltage drop occurring across the armature winding.


Step 3: Conclusion:

Therefore, $R_a$ represents the armature resistance, making option (D) the correct answer.
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