Question:
Two shortest harmonics of an organ pipe open at both ends are \(200\) Hz and \(240\) Hz. The fundamental frequency is
Two shortest harmonics of an organ pipe open at both ends are \(200\) Hz and \(240\) Hz. The fundamental frequency is
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In an open pipe, all harmonics are present:
\[
f_n=nf
\]
So the difference between consecutive harmonics equals the fundamental frequency.
Updated On: Apr 29, 2026
- \(40\) Hz
- \(20\) Hz
- \(30\) Hz
- \(80\) Hz
- \(50\) Hz
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The Correct Option is A
Solution and Explanation
For an open organ pipe, allowed frequencies are:
\[
f_n=nf
\]
So all harmonics are integer multiples of the fundamental frequency.
The two given frequencies are:
\[
200\text{ Hz},\quad 240\text{ Hz}
\]
Their difference is:
\[
240-200=40\text{ Hz}
\]
Thus the fundamental frequency is:
\[
\boxed{40\text{ Hz}}
\]
Hence,
\[
\boxed{(A)\ 40\text{ Hz}}
\]
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