The dimension of Planck's constant \( h \) can be derived from its relation to energy and frequency:
\[
E = h \nu
\]
Where \( E \) is the energy, \( h \) is Planck's constant, and \( \nu \) is the frequency. The dimensions of energy are:
\[
[E] = M L^2 T^{-2}
\]
And the dimensions of frequency are:
\[
[\nu] = T^{-1}
\]
From the equation \( E = h \nu \), we get:
\[
[h] = \frac{E}{\nu} = \frac{M L^2 T^{-2}}{T^{-1}} = M L^2 T^{-1}
\]
This is the same as the dimension of angular momentum, which is:
\[
[L] = M L^2 T^{-1}
\]
Thus, the dimension of Planck's constant is the same as that of angular momentum.
Final Answer: (C) Angular momentum