Two objects of masses \( 1\,\text{kg} \) and \( 2\,\text{kg} \) are moving towards each other with accelerations \( 2\,\text{m s}^{-2} \) and \( 3\,\text{m s}^{-2} \) respectively on a smooth horizontal surface. The acceleration of centre of mass of the system is
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Always assign proper sign based on direction before applying formula.
\( \frac{4}{3}\,\text{m s}^{-2} \) in the direction of acceleration of 2 kg mass
\( \frac{2}{3}\,\text{m s}^{-2} \) in the direction of acceleration of 1 kg mass
\( \frac{2}{3}\,\text{m s}^{-2} \) in the direction of acceleration of 2 kg mass
\( \frac{4}{3}\,\text{m s}^{-2} \) in the direction of acceleration of 1 kg mass
zero
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The Correct Option isA
Solution and Explanation
Concept:
\[
a_{cm} = \frac{m_1 a_1 + m_2 a_2}{m_1 + m_2}
\]
Step 1: Take direction carefully.
Let acceleration of 2 kg mass be positive.
\[
a_{cm} = \frac{1(-2) + 2(3)}{3} = \frac{-2 + 6}{3} = \frac{4}{3}
\]
Direction → towards 2 kg mass.