Question:
Four identical point masses are placed at the corners of a square ABCD and the centre of mass lies at the centre O of the square. If the mass at B is removed, then the centre of mass lies at the point
Four identical point masses are placed at the corners of a square ABCD and the centre of mass lies at the centre O of the square. If the mass at B is removed, then the centre of mass lies at the point
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Removing a mass shifts the centre of mass in the direction opposite to the removed mass.
Updated On: Apr 24, 2026
- O
- on OB
- on OA
- on OD
- on OC
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The Correct Option is
Solution and Explanation
Step 1: Understanding the Concept:
Centre of mass of symmetric system lies at geometric centre. Removing one mass shifts COM opposite to removed mass.
Step 2: Detailed Explanation:
Initially, 4 equal masses at A, B, C, D = COM( center of mass) at O.
When mass at B is removed, symmetry is disturbed.
Remaining masses are at A, C, D.
Step 3:
COM shifts away from missing mass (B) towards the opposite side.
Opposite direction of B is towards point C.
Step 4: Final Answer:}
Centre of mass lies on line OC.
Centre of mass of symmetric system lies at geometric centre. Removing one mass shifts COM opposite to removed mass.
Step 2: Detailed Explanation:
Initially, 4 equal masses at A, B, C, D = COM( center of mass) at O.
When mass at B is removed, symmetry is disturbed.
Remaining masses are at A, C, D.
Step 3:
COM shifts away from missing mass (B) towards the opposite side.
Opposite direction of B is towards point C.
Step 4: Final Answer:}
Centre of mass lies on line OC.
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