Question:

Two identical piano wires, when tuned to a fundamental frequency of 400 Hz, produce no beats. One wire is then slightly tightened, and the beat frequency heard is 2 Hz. What is the new fundamental frequency of the tightened wire?

Show Hint

Tighten = Frequency Up. Loosen = Frequency Down.
  • 398 Hz
  • 402 Hz
  • 404 Hz
  • 396 Hz
Show Solution
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The Correct Option is B

Solution and Explanation


Step 1: Concept

The frequency of a stretched string $n$ is directly proportional to the square root of its tension ($n \propto \sqrt{T}$).

Step 2: Meaning

Tightening a wire increases its tension, which necessarily increases its frequency.

Step 3: Analysis

Beat frequency is the difference between two frequencies ($|n_1 - n_2| = 2$ Hz). Since the wire was tightened, the new frequency must be $400 + 2 = 402$ Hz.

Step 4: Conclusion

The new fundamental frequency is 402 Hz.
Final Answer: (B)
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