Question:
Two identical circular rods of same diameter and length are subjected to same axial tensile force. One is mild steel and other aluminium. Which is correct?
Two identical circular rods of same diameter and length are subjected to same axial tensile force. One is mild steel and other aluminium. Which is correct?
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Lower Young’s modulus → higher deformation under same load.
Updated On: May 22, 2026
- Both rods elongate by same amount
- Mild steel elongates more
- Aluminium elongates more
- All stresses, strains equal
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The Correct Option is C
Solution and Explanation
Concept:
Axial elongation:
\[
\delta = \frac{PL}{AE}
\]
Step 1: Given conditions.
Same: \[ P, L, A \] Different: \[ E_{\text{steel}} > E_{\text{aluminium}} \]
Step 2: Compare elongations.
\[ \delta \propto \frac{1}{E} \] Thus: \[ \delta_{\text{aluminium}} > \delta_{\text{steel}} \]
Step 3: Physical reasoning.
Aluminium is less stiff → more deformation. Final Answer: \[ \boxed{\text{Aluminium elongates more}} \]
Step 1: Given conditions.
Same: \[ P, L, A \] Different: \[ E_{\text{steel}} > E_{\text{aluminium}} \]
Step 2: Compare elongations.
\[ \delta \propto \frac{1}{E} \] Thus: \[ \delta_{\text{aluminium}} > \delta_{\text{steel}} \]
Step 3: Physical reasoning.
Aluminium is less stiff → more deformation. Final Answer: \[ \boxed{\text{Aluminium elongates more}} \]
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