Question:
Two bulbs of equal power are connected in parallel and they totally consume 110 W at 220 V. The resistance of each bulb is
Two bulbs of equal power are connected in parallel and they totally consume 110 W at 220 V. The resistance of each bulb is
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Parallel → voltage same; Series → current same.
Updated On: May 2, 2026
- $550 \Omega$
- $440 \Omega$
- $330 \Omega$
- $880 \Omega$
- $660 \Omega$
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The Correct Option is D
Solution and Explanation
Concept:
Power relation:
\[
P = \frac{V^2}{R}
\]
Step 1: Total power \[ P_{\text{total}} = 110 \text{ W} \] Since bulbs are identical: \[ P_{\text{each}} = 55 \text{ W} \]
Step 2: In parallel Each bulb gets full voltage: \[ V = 220 \text{ V} \]
Step 3: Apply formula \[ 55 = \frac{220^2}{R} \] \[ R = \frac{220^2}{55} = 880 \Omega \] Physical Insight: Parallel → same voltage → power splits equally. Final Answer: \[ 880 \Omega \]
Step 1: Total power \[ P_{\text{total}} = 110 \text{ W} \] Since bulbs are identical: \[ P_{\text{each}} = 55 \text{ W} \]
Step 2: In parallel Each bulb gets full voltage: \[ V = 220 \text{ V} \]
Step 3: Apply formula \[ 55 = \frac{220^2}{R} \] \[ R = \frac{220^2}{55} = 880 \Omega \] Physical Insight: Parallel → same voltage → power splits equally. Final Answer: \[ 880 \Omega \]
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