Question:
When an electric potential of 200 V is maintained between the ends of a conductor, a current of 3 A flows through it. The amount of heat energy dissipated in the time interval 25 s is
When an electric potential of 200 V is maintained between the ends of a conductor, a current of 3 A flows through it. The amount of heat energy dissipated in the time interval 25 s is
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$1 \text{ kJ} = 1000 \text{ Joules}$.
Updated On: Apr 27, 2026
- 3 kJ
- 22.5 kJ
- 7.5 kJ
- 6 kJ
- 15 kJ
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The Correct Option is
Solution and Explanation
Step 1: Concept
Heat dissipated $H = VIt$.
Step 2: Meaning
Energy equals voltage times current times time.
Step 3: Analysis
$H = 200 \times 3 \times 25 = 15000$ J.
Step 4: Conclusion
$15000$ J $= 15$ kJ.
Final Answer: (E)
Heat dissipated $H = VIt$.
Step 2: Meaning
Energy equals voltage times current times time.
Step 3: Analysis
$H = 200 \times 3 \times 25 = 15000$ J.
Step 4: Conclusion
$15000$ J $= 15$ kJ.
Final Answer: (E)
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