Step 1: Understanding the Concept
Let \(\varphi\) be the angle between \(\vec{AB}\) and \(\vec{AD}\). The new side \(AD'\) is in the same plane, perpendicular to \(AB\), and obtained by an acute rotation.
Step 2: Key Formula or Approach
\[ \cos\varphi=\frac{\vec{AB}\cdot\vec{AD}}{|\vec{AB}||\vec{AD}|} \]
Step 3: Detailed Explanation
\(\vec{AB}\cdot\vec{AD}=-2+20+22=40\), \(|\vec{AB}|=\sqrt{4+100+121}=15\), \(|\vec{AD}|=3\).
\(\cos\varphi=\dfrac{40}{45}=\dfrac89\), so \(\sin\varphi=\dfrac{\sqrt{17}}{9}\).
To reach a direction at \(90^{\circ}\) from \(AB\), the acute rotation is \(\alpha=90^{\circ}-\varphi\).
\[ \cos\alpha=\sin\varphi=\frac{\sqrt{17}}{9} \]
Final Answer:
\(\cos\alpha=\dfrac{\sqrt{17}}{9}\), option (B).
\[ \boxed{\dfrac{\sqrt{17}}{9}\ \text{(B)}} \]