Question:

Three vectors \(\hat{\mathrm{i}}-\hat{\mathrm{k}}, \lambda \hat{\mathrm{i}}+\hat{\mathrm{j}}+(1-\lambda) \hat{\mathrm{k}}\) and \(\mu \hat{\mathrm{i}}+\lambda \hat{\mathrm{j}}+(1+\lambda-\mu) \hat{\mathrm{k}}\) represents coterminous edges of a parallelopiped, then the volume of the parallelopiped depends on.

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The volume is the absolute value of the scalar triple product, which is the determinant of the three vectors.
Updated On: Nov 13, 2026
  • only \(\lambda\)
  • only \(\mu\)
  • both \(\lambda\) and \(\mu\)
  • neither \(\lambda\) nor \(\mu\)
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The Correct Option is D

Solution and Explanation

Step 1: Understanding the Concept
Volume of a parallelepiped \(=|[\bar{a}\ \bar{b}\ \bar{c}]|\), the absolute value of the determinant of the components.

Step 2: Write the Determinant
Rows: \((1,0,-1)\), \((\lambda,1,1-\lambda)\), \((\mu,\lambda,1+\lambda-\mu)\).

Step 3: Expand
Determinant \(=1\left[(1+\lambda-\mu)-\lambda(1-\lambda)\right]-1\left[\lambda^{2}-\mu\right]\).
\(=(1-\mu+\lambda^{2})-\lambda^{2}+\mu=1\).

Step 4: Conclusion
The volume is 1 whatever \(\lambda\) and \(\mu\) are, so it depends on neither, option (D).

Final Answer:
The volume is always 1, so it depends on neither \(\lambda\) nor \(\mu\). \[ \boxed{\text{(D) }\text{neither }\lambda\text{ nor }\mu} \]
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