Question:

Three equal masses M are placed at the vertices A, B, and C of an equilateral triangle. The net force acting on a unit mass placed at the centroid O is:

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The center of symmetry for identical masses always has zero net field.
Updated On: Apr 8, 2026
  • Zero
  • $3GM^{2}/L^{2}$
  • $GM/L^{2}$
  • $2GM/L^{2}$
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The Correct Option is A

Solution and Explanation

Step 1: Concept
The net force is the vector sum of gravitational intensities from each mass.
Step 2: Analysis

At the centroid of an equilateral triangle with equal masses at the vertices, the forces $\vec{F}_{1}, \vec{F}_{2}, \vec{F}_{3}$ are equal in magnitude and separated by $120^{\circ}$.
Step 3: Conclusion

The vector sum $\vec{F}_{1} + \vec{F}_{2} + \vec{F}_{3} = 0$ because the resultant of any two is equal and opposite to the third.
Final Answer: (A)
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