Question:

A force of 5 N gives a mass \(M_1\) an acceleration equal to \(8 \, \text{m/s}^2\) and \(M_2\) an acceleration equal to \(24 \, \text{m/s}^2\). What is the acceleration, if both masses are tied together?

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When same force acts separately, find masses first, then combine and apply Newton’s law again.
Updated On: Apr 15, 2026
  • \(16 \, \text{m/s}^2\)
  • \(6 \, \text{m/s}^2\)
  • \(12 \, \text{m/s}^2\)
  • \(4 \, \text{m/s}^2\)
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The Correct Option is B

Solution and Explanation

Concept: From Newton’s second law: \[ F = ma \Rightarrow m = \frac{F}{a} \]

Step 1:
Find masses.
\[ M_1 = \frac{5}{8}, \quad M_2 = \frac{5}{24} \]

Step 2:
Total mass.
\[ M = \frac{5}{8} + \frac{5}{24} = \frac{15 + 5}{24} = \frac{20}{24} = \frac{5}{6} \]

Step 3:
Acceleration of system.
\[ a = \frac{F}{M} = \frac{5}{5/6} = 6 \, \text{m/s}^2 \]
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