Question:

The work done in blowing a soap bubble of radius $r$ and surface tension $T$ is:

Show Hint

Liquid drop = 1 surface; Soap bubble = 2 surfaces.
Updated On: Apr 8, 2026
  • $4\pi r^{2} T$
  • $8\pi r^{2} T$
  • $2\pi r^{2} T$
  • $16\pi r^{2} T$
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is B

Solution and Explanation

Step 1: Concept
Work done $W = T \times \Delta A$.
Step 2: Analysis

A soap bubble has two free surfaces (inner and outer). Surface area of one side $= 4\pi r^{2}$. Total area change $= 2 \times 4\pi r^{2} = 8\pi r^{2}$.
Step 3: Conclusion

$W = 8\pi r^{2} T$.
Final Answer: (B)
Was this answer helpful?
0
0

Top MET Physics Questions

View More Questions

Top MET mechanical properties of solids Questions

Top MET Questions

View More Questions