The weights of $A$, $B$ and $C$ are in the ratio $8:7:5$. $A$'s weight is $60\%$ more than $C$'s. Find the weight of $B$.
I. Total weight of $A,B,C$ is $300$ kg.
II. Difference between $A$'s and $C$'s weight is $45$ kg.
I + II together necessary.
Let $A: B: C = 8:7:5$ (consistent with $A=1.6C$).
I: $8k+7k+5k=300 \Rightarrow k=15 \Rightarrow B=7k=105$ kg (sufficient).
II: $A-C=45$ and with $A=8k,\,C=5k$ gives $3k=45\Rightarrow k=15 \Rightarrow B=105$ kg (sufficient).
Either statement gives $B$.
Instead of introducing a multiplier variable, express each person's weight as a percentage of the total, since the ratio \( 8:7:5 \) sums to \( 20 \) parts: \( A=40\% \), \( B=35\% \), \( C=25\% \) of the total weight.
Both statements independently fix the total weight via the percentage shares, so either one alone answers the question.
Hence, the correct answer is If either I alone or II alone is sufficient.
