Question:

The time period of a geostationary satellite at a height 36000 km is 24 h. A spy satellite orbits earth at a height 6400 km. What will be the time period of spy satellite? [Radius of the earth = 6400 km]

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The time period of a geostationary satellite at a height 36000 km is 24 h. A spy satellite orbits earth at a height 6400 km. What will be the time period of spy satellite? [Radius of the earth = 6400 km]
Updated On: Apr 15, 2026
  • 5 h
  • 4 h
  • 3 h
  • 12 h
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The Correct Option is B

Solution and Explanation

Step 1: Kepler's Law
$T^2 \propto R^3$.
Step 2: Radii
$R_1 = 36000 + 6400 = 42400 \text{ km}$. $R_2 = 6400 + 6400 = 12800 \text{ km}$.
Step 3: Calculation
$\frac{T_2}{T_1} = \left(\frac{R_2}{R_1}\right)^{1.5} \approx \left(\frac{12800}{42400}\right)^{1.5} \approx 4 \text{ h}$.
Final Answer: (B)
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