Step 1: Refraction at spherical surface: $\frac\mu₂v - \frac\mu₁u = \frac\mu₂ - \mu₁R$. Here $\mu₁ = 1$ (air), $\mu₂ = 4/3$ (water), $u = -7.5$ cm (object outside), $R = +2.5$ cm.
Step 2: $\frac4/3v - \frac1-7.5 = \frac4/3 - 12.5 = \frac1/32.5 = \frac17.5$. $\frac43v + \frac17.5 = \frac17.5 → \frac43v = 0 → v = ∞$. That suggests image at infinity. Alternatively, for a sphere, the image is formed at the centre? Given answer is 10 cm from centre.