Concept:
An alternating voltage continuously changes its magnitude and direction with time.
For a sinusoidal alternating voltage
\[
V=V_0\sin\omega t,
\]
two important quantities are frequently used:
• Root Mean Square (RMS) Value
• Average Value over a complete cycle
The RMS value represents the equivalent DC voltage that would produce the same heating effect in a resistor.
The average value over one complete cycle is obtained by averaging all instantaneous values over the full period.
Step 1: Determine the RMS value of the alternating voltage.
For a sinusoidal voltage
\[
V=V_0\sin\omega t,
\]
the RMS value is given by the standard relation
\[
V_{\text{rms}}
=
\frac{V_0}{\sqrt2}.
\]
This result follows from the definition
\[
V_{\text{rms}}
=
\sqrt{\frac{1}{T}\int_0^T V^2\,dt}.
\]
Substituting
\[
V=V_0\sin\omega t,
\]
one obtains
\[
V_{\text{rms}}
=
\frac{V_0}{\sqrt2}.
\]
Thus,
\[
\boxed{V_{\text{rms}}=\frac{V_0}{\sqrt2}}
\]
Step 2: Determine the average value over one complete cycle.
The average value is
\[
V_{\text{avg}}
=
\frac{1}{T}
\int_0^T
V_0\sin\omega t\,dt.
\]
Over one complete cycle, the positive half-cycle and negative half-cycle are equal in magnitude but opposite in sign.
Therefore, the positive area exactly cancels the negative area.
Hence,
\[
V_{\text{avg}}=0.
\]
Thus,
\[
\boxed{V_{\text{avg}}=0}
\]
Step 3: Compare with the given options.
We have obtained
\[
V_{\text{rms}}
=
\frac{V_0}{\sqrt2}
\]
and
\[
V_{\text{avg}}
=
0.
\]
This corresponds exactly to Option (C).
Step 4: State the final answer.
Therefore,
\[
\boxed{
V_{\text{rms}}=\frac{V_0}{\sqrt2},
\qquad
V_{\text{avg}}=0
}
\]
Hence, the correct answer is
\[
\boxed{\text{(C)}}.
\]