Question:
The relative basic strength of the compounds is correctly shown in the option
The relative basic strength of the compounds is correctly shown in the option
Show Hint
Electron withdrawing groups decrease basic strength because they reduce the availability of the lone pair on nitrogen for proton donation.
Updated On: Jun 22, 2026
- \(NH_2OH\gt NH_3\gt N_2H_4\)
- \(N_2H_4\gt NH_2OH\gt NH_3\)
- \(NH_3\gt N_2H_4\gt NH_2OH\)
- \(N_2H_4\gt NH_3\gt NH_2OH\)
Show Solution
Verified By Collegedunia
The Correct Option is C
Solution and Explanation
Step 1: Recall the factor affecting basic strength.
Basic strength depends on the availability of the lone pair of electrons on nitrogen atom for donation.
Greater the availability of the lone pair, greater is the basic strength
Step 2: Compare \(NH_3\) and \(NH_2OH\).
In \[ NH_2OH \] the oxygen atom is highly electronegative and exerts a strong \[ -I \] (inductive withdrawing) effect.
This decreases the electron density on nitrogen and reduces the availability of the lone pair.
Therefore, \[ NH_2OH \] is less basic than \[ NH_3 \]
Step 3: Compare \(NH_3\) and \(N_2H_4\).
In hydrazine, \[ N_2H_4 \] the adjacent nitrogen atom also exerts an electron withdrawing effect on the other nitrogen atom.
Thus, the lone pair on nitrogen becomes slightly less available compared to ammonia.
Hence, \[ NH_3 \] is more basic than \[ N_2H_4 \] However, the electron withdrawing effect of nitrogen is weaker than that of oxygen, so \[ N_2H_4 \] is more basic than \[ NH_2OH \]
Step 4: Arrange the compounds in decreasing basic strength.
Therefore, \[ NH_3\gt N_2H_4\gt NH_2OH \]
Step 5: Final conclusion.
Hence, the correct order of relative basic strength is \[ \boxed{NH_3\gt N_2H_4\gt NH_2OH} \]
Basic strength depends on the availability of the lone pair of electrons on nitrogen atom for donation.
Greater the availability of the lone pair, greater is the basic strength
Step 2: Compare \(NH_3\) and \(NH_2OH\).
In \[ NH_2OH \] the oxygen atom is highly electronegative and exerts a strong \[ -I \] (inductive withdrawing) effect.
This decreases the electron density on nitrogen and reduces the availability of the lone pair.
Therefore, \[ NH_2OH \] is less basic than \[ NH_3 \]
Step 3: Compare \(NH_3\) and \(N_2H_4\).
In hydrazine, \[ N_2H_4 \] the adjacent nitrogen atom also exerts an electron withdrawing effect on the other nitrogen atom.
Thus, the lone pair on nitrogen becomes slightly less available compared to ammonia.
Hence, \[ NH_3 \] is more basic than \[ N_2H_4 \] However, the electron withdrawing effect of nitrogen is weaker than that of oxygen, so \[ N_2H_4 \] is more basic than \[ NH_2OH \]
Step 4: Arrange the compounds in decreasing basic strength.
Therefore, \[ NH_3\gt N_2H_4\gt NH_2OH \]
Step 5: Final conclusion.
Hence, the correct order of relative basic strength is \[ \boxed{NH_3\gt N_2H_4\gt NH_2OH} \]
Was this answer helpful?
0
0
Top AP EAPCET Chemistry Questions
- The four quantum numbers of the valence electron of potassium are :
- The volume of $0.02\, M$ acidified permanganate solution required for complete reaction of $60\, mL$ of $0.01\, MI^{-}$ ion solution to form $I_2$ in $mL$ is
- In which of the following the election gain enthalpy of elements is correctly arranged?
- The radii of $ \text{F,}{{\text{F}}^{-}}\text{O} $ and $ {{\text{O}}^{2-}} $ are in the order
- Which of the following has the highest first ionization potential?
View More Questions
Top AP EAPCET Amines Questions
- Given below are two statements
Assertion (A): Ethylamine is stronger base than ammonia
Reason (R): It is due to $-$I effect of ethyl group
The correct answer is Basicity order of the following amines in aqueous medium
i) N-Methylaniline i
i) N, N-Dimethylaniline
iii) Aniline- Which of the following produces nitrogen gas after the reaction with nitrous acid?
- Hydrolysis products of isobutyl isonitrile are:
- Identify the compounds which can react with chloroform and alcoholic KOH and give substances with offensive odour (Carbylamine test).
View More Questions
Top AP EAPCET Questions
- A body is projected from the ground at an angle of $\tan^{-1} \left( \frac{8}{7}\right)$ with the horizontal. The ratio of the maximum height attained by it to its range is
- The four quantum numbers of the valence electron of potassium are :
- A lens forms real and virtual images of an object, when the object is at $u_{1}$ and $u_{2}$ distances respectively. If the size of the virtual image is double that of the real image, then the focal length of the lens is (take, the magnification of the real image as $m$ )
- Two spheres $P$ and $Q$, each of mass $200\, g$ are attached to a string of length one metre as shown in the figure. The string and the spheres are then whirled in a horizontal circle about $O$ at a constant angular speed. The ratio of the tension in the string between $P$ and $Q$ to that of between $P$ and $O$ is $(P$ is at mid-point of the line joining $O$ and $Q$ )
- The volume of $0.02\, M$ acidified permanganate solution required for complete reaction of $60\, mL$ of $0.01\, MI^{-}$ ion solution to form $I_2$ in $mL$ is
View More Questions