Question:
The recoil velocity of a $ 4.0\, kg $ rifle that shoots a $ 0.050\, kg $ bullet at a speed of $ 280\text{ }m{{s}^{-1}} $ is:
The recoil velocity of a $ 4.0\, kg $ rifle that shoots a $ 0.050\, kg $ bullet at a speed of $ 280\text{ }m{{s}^{-1}} $ is:
Updated On: Aug 1, 2022
- $ +3.5\text{ }m{{s}^{-1}} $
- $ -3.5\text{ }m{{s}^{-1}} $
- $ -\sqrt{(3.5)}\text{ }m{{s}^{-1}} $
- $ +\sqrt{(3.5)}\text{ }m{{s}^{-1}} $
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The Correct Option is B
Solution and Explanation
$ {{m}_{1}}{{u}_{1}}+{{m}_{2}}{{u}_{2}}=0 $
$ \Rightarrow $ $ {{u}_{1}}=-\frac{{{m}_{2}}{{u}_{2}}}{{{m}_{1}}} $ $ =\frac{0.050\times 280}{4}=-3.5\,m{{s}^{-1}} $
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Concepts Used:
Momentum
It can be defined as "mass in motion." All objects have mass; so if an object is moving, then it is called as momentum.
the momentum of an object is the product of mass of the object and the velocity of the object.
Momentum = mass • velocity
The above equation can be rewritten as
p = m • v
where m is the mass and v is the velocity.
Momentum is a vector quantity and the direction of the of the vector is the same as the direction that an object.