Question

A hockey player hits a ball with an impulse of 15 Ns. If time of hit is 0.2 s, the average force exerted by the player on the ball is

• A. 75 N
• B. 50 N
• C. 15 N
• D. 20 N
• E. 25 N

Hint:

Impulse is the product of force and time. To find the average force, divide the impulse by the time duration.

Answer 1

The Correct Option is A

Impulse is given by the equation: \[ \text{Impulse} = F_{\text{avg}} \times \Delta t \] Where: - \( F_{\text{avg}} \) is the average force exerted - \( \Delta t \) is the time of impact Given: - Impulse = 15 Ns - \( \Delta t = 0.2 \, \text{s} \) We can rearrange the equation to solve for the average force: \[ F_{\text{avg}} = \frac{\text{Impulse}}{\Delta t} \] \[ F_{\text{avg}} = \frac{15}{0.2} = 75 \, \text{N} \] Thus, the correct answer is (A) 75 N.