Question:
The reagent \(P\) used for the reaction is
The reagent \(P\) used for the reaction is
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Hofmann bromamide reaction converts:
\[
RCONH_2 \rightarrow RNH_2
\]
with loss of one carbon atom using:
\[
Br_2/NaOH
\]
Updated On: Jun 25, 2026
- \(Zn-Hg/HCl\)
- \(HCl/SnCl_2\)
- \(Br_2/NaOH\)
- \(ZnCl/HCl\)
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The Correct Option is C
Solution and Explanation
Step 1: Identify the type of transformation.
The given reaction converts an amide: \[ RCONH_2 \] into a primary amine: \[ RNH_2 \] with loss of one carbon atom.
Step 2: Recall Hofmann bromamide reaction.
Amides react with: \[ Br_2/NaOH \] to form primary amines containing one carbon less than the parent amide.
General reaction: \[ RCONH_2 \xrightarrow{Br_2/NaOH} RNH_2 \]
Step 3: Apply to the given compound.
Cyclopentane carboxamide undergoes Hofmann bromamide degradation: \[ \text{Cyclopentane carboxamide} \xrightarrow{Br_2/NaOH} \text{Cyclopentylamine} \] Thus, reagent \(P\) is: \[ Br_2/NaOH \]
Step 4: Final conclusion.
Hence, the correct reagent is \[ \boxed{Br_2/NaOH} \]
The given reaction converts an amide: \[ RCONH_2 \] into a primary amine: \[ RNH_2 \] with loss of one carbon atom.
Step 2: Recall Hofmann bromamide reaction.
Amides react with: \[ Br_2/NaOH \] to form primary amines containing one carbon less than the parent amide.
General reaction: \[ RCONH_2 \xrightarrow{Br_2/NaOH} RNH_2 \]
Step 3: Apply to the given compound.
Cyclopentane carboxamide undergoes Hofmann bromamide degradation: \[ \text{Cyclopentane carboxamide} \xrightarrow{Br_2/NaOH} \text{Cyclopentylamine} \] Thus, reagent \(P\) is: \[ Br_2/NaOH \]
Step 4: Final conclusion.
Hence, the correct reagent is \[ \boxed{Br_2/NaOH} \]
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