Step 1: Understanding the Concept
"At least once" is the complement of "never". Since the trials are independent, the probability of never is the product of the failure probabilities.
Step 2: Compute
\(P(\text{A fails in one trial}) = 1 - 0.4 = 0.6\).
\[ P(\text{never}) = 0.6^3 = 0.216 \]
\[ P(\text{at least once}) = 1 - 0.216 = 0.784 \]
Option (A), 0.216, is the probability of never, and (C), 0.064, is the probability of three successes.
Final Answer:
The probability is 0.784, option (D).
\[ \boxed{0.784} \]