
To solve the problem, we need to compute the expected value \( E(X) \) of the given discrete probability distribution.
1. Use the Formula for Expected Value:
The expected value \( E(X) \) is given by:
\( E(X) = \sum [x_i \cdot P(x_i)] \)
2. Substitute the Given Values:
\[
E(X) = (-4)(0.1) + (-3)(0.2) + (-2)(0.3) + (-1)(0.2) + (0)(0.2)
\]
\[
= -0.4 + (-0.6) + (-0.6) + (-0.2) + 0
\]
\[
= -0.4 - 0.6 - 0.6 - 0.2 = -1.8
\]
3. Conclusion:
The expected value of the distribution is \( -1.8 \)
Final Answer:
The correct option is (A) -1.8.
Determine whether each of the following relations are reflexive, symmetric, and transitive.
Show that the relation R in the set R of real numbers, defined as
R = {(a, b): a ≤ b2 } is neither reflexive nor symmetric nor transitive.
Check whether the relation R defined in the set {1, 2, 3, 4, 5, 6} as
R = {(a, b): b = a + 1} is reflexive, symmetric or transitive.
Four students of class XII are given a problem to solve independently. Their respective chances of solving the problem are: \[ \frac{1}{2},\quad \frac{1}{3},\quad \frac{2}{3},\quad \frac{1}{5} \] Find the probability that at most one of them will solve the problem.
The probability distribution of a random variable \( X \) is given below:
| \( X \) | 1 | 2 | 4 | 2k | 3k | 5k |
|---|---|---|---|---|---|---|
| \( P(X) \) | \( \frac{1}{2} \) | \( \frac{1}{5} \) | \( \frac{3}{25} \) | \( \frac{1}{10} \) | \( \frac{1}{25} \) | \( \frac{1}{25} \) |