Step 1: Recall the concept of motional emf.
When a conductor moves in a magnetic field, an emf is induced:
\[
\varepsilon = B l v
\]
where \(B\) is magnetic field, \(l\) is length, and \(v\) is velocity.
Step 2: Determine the induced current.
If the circuit has resistance \(R\), then current is:
\[
I = \frac{\varepsilon}{R} = \frac{Blv}{R}
\]
Step 3: Find the magnetic force on the conductor.
The force acting on the conductor is:
\[
F = B l I
\]
Substitute \(I\):
\[
F = B l \cdot \frac{Blv}{R} = \frac{B^2 l^2 v}{R}
\]
Step 4: Write the expression for power.
Power required is:
\[
P = F \cdot v
\]
Step 5: Substitute the force expression.
\[
P = \frac{B^2 l^2 v}{R} \cdot v
\]
\[
P = \frac{B^2 l^2}{R} v^2
\]
Step 6: Identify proportionality.
\[
P \propto v^2
\]
Step 7: Final answer.
\[
\boxed{v^2}
\]
which matches option \((2)\).