Step 1: Thermodynamic Analysis of Water Heating:
Water has a remarkably high specific heat capacity ($c \approx 4184\text{ J/kg}^\circ\text{C}$). To raise the temperature of a standard volume of water (e.g., 10 to 25 liters) in a reasonable timeframe, a significant thermal energy input ($Q$) is required:
$$Q = m c \Delta T$$
Where $m$ is the mass of water and $\Delta T$ is the change in temperature.
Step 2: Estimating Power Requirements:
The electrical power ($P$) must deliver this thermal energy over a time interval ($t$):
$$P = \frac{Q}{\eta \cdot t}$$
Where $\eta$ represents the efficiency of the heating element. To heat household water efficiently, a domestic appliance must operate at high wattages.
Step 3: Evaluating Power Ratings of Appliances:
- $10\text{ to }100\text{ W}$: Appropriate for low-power electronics or incandescent light bulbs.
- $100\text{ to }500\text{ W}$: Appropriate for soldering irons or hand-mixers.
- $500\text{ to }1000\text{ W}$: Appropriate for dry electric irons or sandwich makers.
- $1000\text{ to }3000\text{ W}$ ($1\text{ to }3\text{ kW}$): Standard ratings for high-power thermal appliances like geysers, immersion rods, and electric kettles.
Therefore, option (D) is the correct choice.