Question:

The power delivered by the battery shown in the figure is - (Take the forward and reverse biased resistances of the diode are zero and infinity respectively)

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For circuits with ideal diodes:
- A forward-biased diode behaves like a short circuit (zero resistance).
- A reverse-biased diode behaves like an open circuit (infinite resistance). Simplify the circuit accordingly before solving.
Updated On: May 5, 2026
  • \(2.50 \, W\)
  • \(5.00 \, W\)
  • \(7.50 \, W\)
  • \(3.75 \, W\)
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The Correct Option is A

Solution and Explanation

Step 1: Identify conducting path

Since diodes are ideal:

  • \( D_1 \) is forward biased → conducting
  • \( D_2 \) is reverse biased → non-conducting

The circuit reduces to a \( 10\,\Omega \) resistor connected across a \( 5\,\text{V} \) battery.

Step 2: Calculate current

\[ I = \frac{V}{R} = \frac{5}{10} = 0.5 \, \text{A} \]

Step 3: Power delivered by battery

\[ P = V I = 5 \times 0.5 = 2.5 \, \text{W} \]

Final Answer: \( 2.5 \, \text{W} \)

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