Question:
The oxidation state of Fe in ferrate ion is:
The oxidation state of Fe in ferrate ion is:
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In oxyanions, oxygen is usually \(-2\); use charge balance method to find central atom oxidation state.
Updated On: Jun 19, 2026
- +2
- +3
- +5
- +6
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The Correct Option is D
Solution and Explanation
Step 1: Understanding ferrate ion composition.
Ferrate ion is represented as \(FeO_4^{2-}\), where oxygen has a fixed oxidation state of \(-2\).
Step 2: Assigning oxidation numbers.
Let oxidation state of Fe be \(x\). Since there are four oxygen atoms: \[ 4 \times (-2) = -8 \]
Step 3: Writing total charge equation.
Overall charge of ion is \(-2\), so: \[ x - 8 = -2 \]
Step 4: Solving for x.
\[ x = +6 \]
Step 5: Final interpretation.
Thus, iron exists in its highest oxidation state of +6 in ferrate ion.
Final Answer: \[ \boxed{+6} \]
Ferrate ion is represented as \(FeO_4^{2-}\), where oxygen has a fixed oxidation state of \(-2\).
Step 2: Assigning oxidation numbers.
Let oxidation state of Fe be \(x\). Since there are four oxygen atoms: \[ 4 \times (-2) = -8 \]
Step 3: Writing total charge equation.
Overall charge of ion is \(-2\), so: \[ x - 8 = -2 \]
Step 4: Solving for x.
\[ x = +6 \]
Step 5: Final interpretation.
Thus, iron exists in its highest oxidation state of +6 in ferrate ion.
Final Answer: \[ \boxed{+6} \]
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