Question:
The number of radial nodes possible for \(3p\)-orbital is \(x\) and the number of angular nodes possible for \(4d\)-orbital is \(y\). What is \(x:y\)?
The number of radial nodes possible for \(3p\)-orbital is \(x\) and the number of angular nodes possible for \(4d\)-orbital is \(y\). What is \(x:y\)?
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Remember:
\[
\text{Total Nodes}=n-1
\]
\[
\text{Radial Nodes}=n-l-1
\]
\[
\text{Angular Nodes}=l
\]
For \(p\)-orbitals, \(l=1\); for \(d\)-orbitals, \(l=2\).
Updated On: Jul 29, 2026
- \(3:2\)
- \(2:1\)
- \(1:2\)
- \(1:1\)
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The Correct Option is C
Solution and Explanation
Concept:
For an orbital,
\[
\text{Radial Nodes}=n-l-1
\]
and
\[
\text{Angular Nodes}=l,
\]
where
\[
n=\text{principal quantum number},
\qquad
l=\text{azimuthal quantum number}.
\]
Step 1: Find the radial nodes for \(3p\)-orbital. For \(3p\), \[ n=3, \qquad l=1. \] Therefore, \[ x=n-l-1. \] \[ x=3-1-1. \] \[ x=1. \]
Step 2: Find the angular nodes for \(4d\)-orbital. For \(4d\), \[ n=4, \qquad l=2. \] Hence, \[ y=l=2. \]
Step 3: Calculate the ratio. \[ x:y=1:2. \] Therefore, \[ \boxed{1:2} \] \[ \boxed{\text{Answer = (C)}} \]
Step 1: Find the radial nodes for \(3p\)-orbital. For \(3p\), \[ n=3, \qquad l=1. \] Therefore, \[ x=n-l-1. \] \[ x=3-1-1. \] \[ x=1. \]
Step 2: Find the angular nodes for \(4d\)-orbital. For \(4d\), \[ n=4, \qquad l=2. \] Hence, \[ y=l=2. \]
Step 3: Calculate the ratio. \[ x:y=1:2. \] Therefore, \[ \boxed{1:2} \] \[ \boxed{\text{Answer = (C)}} \]
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