The moment of inertia of a system of two masses $2$ kg and $4$ kg lying in the x-y plane at distances, $2$ m and $4$ m, respectively from the origin about the z-axis is (in $\text{kg m}^2$)
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For point masses:
- Always use $I = mr^2$
- Add contributions of all masses
Concept:
Moment of inertia about an axis is given by:
\[
I = \sum m r^2
\]
where $r$ is the perpendicular distance from the axis.
Step 1: Write contributions of each mass.
For $2$ kg at $2$ m:
\[
I_1 = 2 \times (2)^2 = 2 \times 4 = 8
\]
For $4$ kg at $4$ m:
\[
I_2 = 4 \times (4)^2 = 4 \times 16 = 64
\]
Step 2: Find total moment of inertia.
\[
I = I_1 + I_2 = 8 + 64 = 72
\]