Question:
The maximum number of electrons present in an orbital with \(n=4,\; l=3\) is
The maximum number of electrons present in an orbital with \(n=4,\; l=3\) is
Show Hint
Each orbital can accommodate a maximum of two electrons with opposite spins according to Pauli's exclusion principle.
Updated On: Jun 22, 2026
- \(06\)
- \(14\)
- \(10\)
- \(2\)
Show Solution
Verified By Collegedunia
The Correct Option is D
Solution and Explanation
Step 1: Identify the subshell.
Given, \[ n=4 \] and \[ l=3 \] The azimuthal quantum number \(l=3\) corresponds to the \(f\)-subshell.
Thus, the given orbital belongs to the \(4f\)-subshell.
Step 2: Understand the meaning of an orbital.
An orbital is specified by a unique set of quantum numbers \[ n,\;l,\;m_l \] According to Pauli's exclusion principle, a single orbital can contain a maximum of two electrons with opposite spins.
Step 3: Determine the maximum number of electrons.
Therefore, irrespective of the values of \(n\) and \(l\), one orbital can contain at most \[ 2 \] electrons.
Step 4: Final conclusion.
Hence, the maximum number of electrons present in the orbital is \[ \boxed{2} \]
Given, \[ n=4 \] and \[ l=3 \] The azimuthal quantum number \(l=3\) corresponds to the \(f\)-subshell.
Thus, the given orbital belongs to the \(4f\)-subshell.
Step 2: Understand the meaning of an orbital.
An orbital is specified by a unique set of quantum numbers \[ n,\;l,\;m_l \] According to Pauli's exclusion principle, a single orbital can contain a maximum of two electrons with opposite spins.
Step 3: Determine the maximum number of electrons.
Therefore, irrespective of the values of \(n\) and \(l\), one orbital can contain at most \[ 2 \] electrons.
Step 4: Final conclusion.
Hence, the maximum number of electrons present in the orbital is \[ \boxed{2} \]
Was this answer helpful?
0
0
Top AP EAPCET Chemistry Questions
- The four quantum numbers of the valence electron of potassium are :
- The volume of $0.02\, M$ acidified permanganate solution required for complete reaction of $60\, mL$ of $0.01\, MI^{-}$ ion solution to form $I_2$ in $mL$ is
- In which of the following the election gain enthalpy of elements is correctly arranged?
- The radii of $ \text{F,}{{\text{F}}^{-}}\text{O} $ and $ {{\text{O}}^{2-}} $ are in the order
- Which of the following has the highest first ionization potential?
View More Questions
Top AP EAPCET Quantum Numbers and Orbitals Questions
- Maximum number of electrons possible with spin quantum number \(+\frac{1}{2}\) and principal quantum number \(n = 4\) in an atom is:
- Maximum number of electrons theoretically possible for an orbit with principal quantum number n = 6 in an atom is.
- Which of the following sets of quantum numbers is not possible for the electron?
- Which of the following quantum numbers determines the shape of an orbital?
- Quantum number sets of four electrons I, II, III, IV are given below. I. $n=3$, $l=1$, $m_{l}=-1$, $m_{s}=+\frac{1}{2}$ II. $n=4$, $l=1$, $m_{l}=0$, $m_{s}=+\frac{1}{2}$ III. $n=4$, $l=2$, $m_{l}=-2$, $m_{s}=+\frac{1}{2}$ IV. $n=3$, $l=2$, $m_{l}=-1$, $m_{s}=-\frac{1}{2}$ The correct order of the energy of these electrons is
View More Questions
Top AP EAPCET Questions
- A body is projected from the ground at an angle of $\tan^{-1} \left( \frac{8}{7}\right)$ with the horizontal. The ratio of the maximum height attained by it to its range is
- The four quantum numbers of the valence electron of potassium are :
- A lens forms real and virtual images of an object, when the object is at $u_{1}$ and $u_{2}$ distances respectively. If the size of the virtual image is double that of the real image, then the focal length of the lens is (take, the magnification of the real image as $m$ )
- Two spheres $P$ and $Q$, each of mass $200\, g$ are attached to a string of length one metre as shown in the figure. The string and the spheres are then whirled in a horizontal circle about $O$ at a constant angular speed. The ratio of the tension in the string between $P$ and $Q$ to that of between $P$ and $O$ is $(P$ is at mid-point of the line joining $O$ and $Q$ )
- The volume of $0.02\, M$ acidified permanganate solution required for complete reaction of $60\, mL$ of $0.01\, MI^{-}$ ion solution to form $I_2$ in $mL$ is
View More Questions