Question:

The low solubility of LiF and that of CsI in water are respectively due to which of the properties of the alkali metal ions?

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Small ions → high lattice enthalpy Large ions → low hydration enthalpy Both can reduce solubility
Updated On: May 2, 2026
  • higher hydration enthalpy of Li$^+$, higher lattice enthalpy of Cs$^+$
  • smaller hydration enthalpy of Li$^+$, higher lattice enthalpy of Cs$^+$
  • smaller lattice enthalpy of Li$^+$, higher hydration enthalpy of Cs$^+$
  • smaller hydration enthalpy of Li$^+$, smaller lattice enthalpy of Cs$^+$
  • higher lattice enthalpy of Li$^+$, smaller hydration enthalpy of Cs$^+$
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The Correct Option is

Solution and Explanation

Concept: Solubility depends on two competing factors
• Lattice enthalpy (energy required to break ionic solid)
• Hydration enthalpy (energy released when ions dissolve)

Step 1: LiF case

• Li$^+$ is very small → strong electrostatic attraction
• Hence, LiF has very high lattice enthalpy
• Even though hydration enthalpy is high, lattice enthalpy dominates
• Therefore, LiF is poorly soluble

Step 2: CsI case

• Cs$^+$ is very large → weak interaction with water
• Hence, hydration enthalpy is small
• So dissolution is not favored
• Therefore, CsI is also poorly soluble Final Answer: \[ \boxed{\text{(E)}} \]
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