Question:
The concentration of hydrogen ions in a sample of soft drink is \( 2\times10^{-4}\,\text{mol L}^{-1} \). Its pH value is ( \( \log 2 = 0.3010 \) )
The concentration of hydrogen ions in a sample of soft drink is \( 2\times10^{-4}\,\text{mol L}^{-1} \). Its pH value is ( \( \log 2 = 0.3010 \) )
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\(\log(ab) = \log a + \log b\)
Updated On: Apr 21, 2026
- \(4.369 \)
- \(3.699 \)
- \(2.369 \)
- \(5.301 \)
- \(3.301 \)
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The Correct Option is B
Solution and Explanation
Concept:
\[
\text{pH} = -\log [H^+]
\]
Step 1: Calculate.
\[ \text{pH} = -\log(2\times10^{-4}) = 4 - \log 2 \] \[ = 4 - 0.301 = 3.699 \]
Step 1: Calculate.
\[ \text{pH} = -\log(2\times10^{-4}) = 4 - \log 2 \] \[ = 4 - 0.301 = 3.699 \]
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