Question

The logic gate equivalent to given logic gate is

• A. OR Gate
• B. AND Gate
• C. NAND Gate
• D. NOR Gate

Hint:

Apply De Morgan's theorem to the NOR of the two inverted inputs.

Answer 1

The Correct Option is B

Step 1: Understanding the Concept
The circuit has two NOT gates, one on each input, and their outputs feed a NOR gate.

Step 2: Write the output
After the NOT gates the signals are \(\bar{A}\) and \(\bar{B}\).
\(Y=\overline{\bar{A}+\bar{B}}\)

Step 3: Apply De Morgan's theorem
\(\overline{\bar{A}+\bar{B}}=\bar{\bar{A}}\cdot\bar{\bar{B}}=A\cdot B\)

Step 4: Conclusion
\(Y=A\cdot B\) is the Boolean expression of an AND gate.

Final Answer:
The circuit is equivalent to an AND gate. \[ \boxed{\text{(B) }\text{AND Gate}} \]