Question:

The IUPAC name of the following complex is \[ [Cr(NH_3)_3(H_2O)_2Cl]Cl_2 \]

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While naming coordination compounds, write ligand names in alphabetical order, determine the oxidation state of the metal, and finally name the counter ion outside the coordination sphere.
Updated On: Jun 18, 2026
  • Triamminediaqua chlorido chromium (III) chloride
  • Diaquatriammine chlorido chromium (III) chloride
  • Chlorido diaquatriammine chromium (III) chloride
  • Triammine diaqua trichlorido chromium (III)
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The Correct Option is A

Solution and Explanation

Step 1: Determine the oxidation state of chromium.
The complex is \[ [Cr(NH_3)_3(H_2O)_2Cl]Cl_2 \] The two chloride ions outside the coordination sphere contribute \[ -2 \] charge.
Hence, the complex ion has charge \[ +2 \] Let oxidation state of chromium be \(x\).
Since \(NH_3\) and \(H_2O\) are neutral ligands, \[ x-1=+2 \] \[ x=+3 \] Therefore, chromium is in the \(+3\) oxidation state.

Step 2: Arrange ligand names alphabetically.

Ligands present are: \[ NH_3 \rightarrow ammine \] \[ H_2O \rightarrow aqua \] \[ Cl^- \rightarrow chlorido \] Ignoring multiplicative prefixes, alphabetical order is \[ ammine,\ aqua,\ chlorido \]

Step 3: Write ligand names with prefixes.

Three ammine ligands: \[ triammine \] Two aqua ligands: \[ diaqua \] One chlorido ligand: \[ chlorido \] Thus, \[ \text{Triamminediaqua chlorido chromium (III)} \] Since chloride is the counter ion outside the coordination sphere, add \[ \text{chloride} \] at the end.

Step 4: Final conclusion.

Hence, the IUPAC name is \[ \boxed{\text{Triamminediaqua chlorido chromium (III) chloride}} \] Therefore, the correct option is (1).
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