Step 1: Understand hydrated metal ion size.
The size of a hydrated ion depends on its charge density. Smaller cations with high charge attract more water molecules strongly, increasing effective hydrated radius.
Step 2: Analyze the given cations.
Ions: Li\(^+\), Na\(^+\), K\(^+\), Cs\(^+\).
Although ionic size increases down the group, the hydrated radius behaves differently due to stronger solvation of small, highly charged cations.
Step 3: Explain effect of solvation.
Li\(^+\) has the smallest ionic radius, but it binds water molecules tightly, forming a large hydration shell. Consequently, the effective size of Li\(^+\) as a hydrated ion is the largest among the given ions.
Step 4: Compare other cations.
Na\(^+\), K\(^+\), Cs\(^+\) have larger bare ionic radii but weaker solvation. Their hydrated radii are smaller than Li\(^+\).
Step 5: Conclude hydrated size trend.
The hydrated radius order:
\[
\text{Li\(^+\)} \gt \text{Na\(^+\)} \gt \text{K\(^+\)} \gt \text{Cs\(^+\)}
\]
Step 6: Final conclusion.
Thus, the hydrated ion with the largest size is:
\[
\boxed{\text{Li\(^+\)}}
\]