Question:

The greatest wavelength of the radiation that will ionize unexcited hydrogen atom is

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Greater wavelength $\Rightarrow$ lower energy (use \( E \propto \frac{1}{\lambda} \)).
Updated On: Apr 21, 2026
  • \(1820\,\text{\AA} \)
  • \(450\,\text{\AA} \)
  • \(910\,\text{\AA} \)
  • \(700\,\text{\AA} \)
  • \(1400\,\text{\AA} \)
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The Correct Option is C

Solution and Explanation

Concept: Ionization energy of hydrogen: \[ E = 13.6\,\text{eV} \]

Step 1:
Relation.
\[ \lambda = \frac{hc}{E} \]

Step 2:
Result.
Maximum wavelength corresponds to minimum energy: \[ \lambda = 910\,\text{\AA} \]
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