Question:

The greatest positive integer which divides \(n(n+1)(n+2)(n+3)\) for all \(n\in\mathbb{N}\), is:

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Product of four consecutive integers is always divisible by \(4!\).
Updated On: Mar 24, 2026
  • \(2\)
  • \(6\)
  • \(24\)
  • \(120\)
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The Correct Option is C

Solution and Explanation


Step 1:
Among four consecutive integers, one is divisible by 4, one by 3, and at least two are even.
Step 2:
Hence product is always divisible by \(4\times3\times2=24\).
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