Question:

\(2^{3n}-7n-1\) is divisible by:

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For powers of 2, check divisibility using modular arithmetic.
Updated On: Mar 24, 2026
  • 64
  • 36
  • 49
  • 25
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The Correct Option is A

Solution and Explanation


Step 1:
Check divisibility by \(2^6=64\).
Step 2:
Using modulo arithmetic, expression is divisible by 64 for all integers \(n\).
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