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2 3n 7n 1 is divisible by
Question:
\(2^{3n}-7n-1\) is divisible by:
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For powers of 2, check divisibility using modular arithmetic.
BITSAT - 2014
BITSAT
Updated On:
Mar 24, 2026
64
36
49
25
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The Correct Option is
A
Solution and Explanation
Step 1:
Check divisibility by \(2^6=64\).
Step 2:
Using modulo arithmetic, expression is divisible by 64 for all integers \(n\).
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