Question:

For n N, xⁿ⁺¹ + (x+1)²n-1 is divisible by:

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Use cube roots of unity to test divisibility by x²+x+1.
Updated On: Mar 18, 2026
  • x
  • x+1
  • x² + x + 1
  • x² - x + 1
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The Correct Option is C

Solution and Explanation


Step 1: Substitution method.
Put x = ω, a cube root of unity.
Step 2: Evaluation.
Expression becomes zero, hence divisible by x² + x + 1.
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