Question:

The following parameter is same for all hydrogen like atoms and ions in their ground state.

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For hydrogen-like atoms, radius, speed and energy depend on atomic number \(Z\), but angular momentum is quantized as \[ L=\frac{nh}{2\pi}. \] For ground state, \(n=1\), so \(L=\dfrac{h}{2\pi}\).
Updated On: Jun 18, 2026
  • Radius of the orbit
  • Speed of the electron
  • Energy of the atom
  • Orbital angular momentum of the electron
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The Correct Option is D

Solution and Explanation

Step 1: Recall Bohr's quantization condition.
According to Bohr's model, \[ mvr=\frac{nh}{2\pi} \] where \(n\) is the principal quantum number.

Step 2: Apply ground state condition.

For ground state, \[ n=1 \] Therefore, \[ mvr=\frac{h}{2\pi} \] This value does not depend on atomic number \(Z\).

Step 3: Check other quantities.

For hydrogen-like species, \[ r_n\propto \frac{n^2}{Z} \] so radius depends on \(Z\).
Also, \[ v_n\propto \frac{Z}{n} \] so speed depends on \(Z\).
Energy is \[ E_n\propto -\frac{Z^2}{n^2} \] so energy also depends on \(Z\).

Step 4: Final conclusion.

Hence, only orbital angular momentum is same for all hydrogen-like atoms and ions in the ground state. \[ \boxed{\text{Orbital angular momentum of the electron}} \]
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