Step 1: Use hydrogen energy level formula.
\[
E_n = -\frac{13.6}{n^2} \, eV
\]
Step 2: Ground state energy.
\[
E_1 = -13.6\,eV
\]
Step 3: Energy required for excitation.
From \(n=1\) to \(n=2\):
\[
\Delta E = 13.6\left(1 - \frac{1}{4}\right) = 10.2\,eV
\]
Step 4: Check given energy.
Given photon energy = 11.0 eV, which is enough to excite electron to \(n=2\) but not exactly higher stable levels.
Step 5: Higher level check.
To reach \(n=3\), required energy:
\[
12.09\,eV > 11.0\,eV
\]
So not possible.
Step 6: Final conclusion.
Thus, electron is excited to \(E_2\).
Final Answer:
\[
\boxed{E_2}
\]