Concept:
• Force per unit length between two parallel long straight currents $I_1$ and $I_2$ separated by distance $r$ is $f = \frac{\mu_0 I_1 I_2}{2\pi r}$.
• Parallel currents in the same direction attract each other; antiparallel currents in opposite directions repel each other.
Step 1: Force per unit length due to Conductor 2
Current in conductor 1 is $2I$ along $+x$. Current in conductor 2 is $I$ along $+x$.
Since currents flow in the same direction, force is attractive (towards conductor 2, i.e., downwards along $-\hat{j}$):
\[ \vec{f}_{12} = \frac{\mu_0 (2I)(I)}{2\pi d} (-\hat{j}) = -\frac{\mu_0 I^2}{\pi d} \hat{j} \]
Step 2: Force per unit length due to Conductor 3
Current in conductor 1 is $2I$ along $+x$. Current in conductor 3 is $3I$ along $-x$.
Since currents flow in opposite directions, force is repulsive (away from conductor 3, i.e., upwards along $+\hat{j}$):
\[ \vec{f}_{13} = \frac{\mu_0 (2I)(3I)}{2\pi (2d)} (+\hat{j}) = +\frac{6 \mu_0 I^2}{4\pi d} \hat{j} = +\frac{3 \mu_0 I^2}{2\pi d} \hat{j} \]
Step 3: Calculate net force per unit length on conductor 1
\[ \vec{f}_{net} = \vec{f}_{12} + \vec{f}_{13} \]
\[ \vec{f}_{net} = \left( \frac{3 \mu_0 I^2}{2\pi d} - \frac{\mu_0 I^2}{\pi d} \right) \hat{j} \]
Take common denominator $2\pi d$:
\[ \vec{f}_{net} = \left( \frac{3 \mu_0 I^2 - 2 \mu_0 I^2}{2\pi d} \right) \hat{j} = +\frac{\mu_0 I^2}{2\pi d} \hat{j} \]
Step 4: Conclusion
Magnitude of net magnetic force per unit length on conductor 1 is $f_{net} = \frac{\mu_0 I^2}{2\pi d}$, directed upwards along the positive y-axis ($+\hat{j}$).