Step 1: Understanding the SHM Equation
- The given displacement equation follows: \[ x = A_0 \cos \left( \frac{\pi}{2} t \right) \] - The amplitude of oscillation is \( A_0 \).
Step 2: Finding the Distance Traveled from \( t = 2 \) to \( t = 5 \)
- At \( t = 2 \): \[ x_2 = A_0 \cos \left( \frac{\pi}{2} \times 2 \right) = A_0 \cos (\pi) = -A_0 \] - At \( t = 5 \): \[ x_5 = A_0 \cos \left( \frac{\pi}{2} \times 5 \right) = A_0 \cos \left( \frac{5\pi}{2} \right) = 0 \] - The particle moves from \( -A_0 \) (extreme) → 0 → \( +A_0 \) (extreme) → 0 (mean position). - Total distance traveled = \( A_0 + 2 A_0 = 3 A_0 \).
Step 3: Finding the Final Position
- At \( t = 5 \), \( x_5 = 0 \), which means the particle is at the mean position.
Step 4: Conclusion
Since the total distance traveled is \( 3A_0 \) and the final position is the mean position, Option (3) is correct.
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