Step 1: Let:
\[
y=x^x
\]
Step 2: Taking logarithm:
\[
\log y=x\log x
\]
Step 3: Differentiate both sides:
\[
\frac{1}{y}\frac{dy}{dx}=\log x+1
\]
Step 4: Therefore:
\[
\frac{dy}{dx}=y(1+\log x)
\]
Step 5: Since \(y=x^x\),
\[
\frac{dy}{dx}=x^x(1+\log x)
\]
\[
\boxed{x^x(1+\log x)}
\]