Question:
The current I1 (in A) flowing through 1 \( \Omega \) resistor in the following circuit is : 
The current I1 (in A) flowing through 1 \( \Omega \) resistor in the following circuit is :
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The 1 V battery is directly across both the middle 2 ohm resistor and the top branch, so find the current in the top branch and divide it equally between the two 1 ohm resistors.
Updated On: Oct 31, 2026
- 0.4
- 0.25
- 0.2
- 0.5
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The Correct Option is C
Solution and Explanation
From the figure, the left and right rails are connected directly to the battery terminals, so the 1 V battery is across (i) the 2 ohm resistor in the middle branch and (ii) the top branch.
Top branch: two 1 ohm resistors in parallel \(=0.5\ \Omega\), in series with the 2 ohm resistor, giving \(2.5\ \Omega\).
Current in the top branch \(=\dfrac{1}{2.5}=0.4\) A.
It divides equally between the two parallel 1 ohm resistors: \(I_1=\dfrac{0.4}{2}=0.2\) A.
Answer: (C) 0.2
Top branch: two 1 ohm resistors in parallel \(=0.5\ \Omega\), in series with the 2 ohm resistor, giving \(2.5\ \Omega\).
Current in the top branch \(=\dfrac{1}{2.5}=0.4\) A.
It divides equally between the two parallel 1 ohm resistors: \(I_1=\dfrac{0.4}{2}=0.2\) A.
Answer: (C) 0.2
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