Question

A particle starts with an initial velocity of 10.0 m/s along x-direction and accelerates uniformly at the rate of 2.0 m/s$^2$. The time taken by the particle to reach the velocity of 60.0 m/s is

• A. 25 S
• B. 20 S
• C. 30 S
• D. 15 S

Answer 1

The Correct Option is A

The correct option is (A): 25 S
\(v = u + at\)
\(60 = 10 + 2t\)
\(2t = 50\)
\(t= 25\) s

Answer 2

We can use the following equation of motion to solve the problem:
v = u + at
Where:
v = final velocity = 60 \(\frac{m}{s}\)
u = initial velocity = 10 \(\frac{m}{s}\)
a = acceleration = 2 \(\frac{m}{s^2}\)
t = time taken
Substituting the given values in the equation, we get:
60 = 10 + 2t
Solving for t, we get:
t = \(\frac {60-10}{2}\) = 25 s
Therefore, the time taken to attain a speed of 60 m/s is 25 seconds.
Hence, the answer is 25 s.
Answer. A

Answer 3

Using the first equation of motion: \[ t = \frac{v - u}{a} \] \[ t = \frac{60 - 10}{2} = \frac{50}{2} = 25 \, \text{sec} \]