A particle starts with an initial velocity of 10.0 m/s along x-direction and accelerates uniformly at the rate of 2.0 m/s$^2$. The time taken by the particle to reach the velocity of 60.0 m/s is
- 25 S
- 20 S
- 30 S
- 15 S
The Correct Option is A
Approach Solution - 1
The correct option is (A): 25 S
\(v = u + at\)
\(60 = 10 + 2t\)
\(2t = 50\)
\(t= 25\) s
Approach Solution -2
We can use the following equation of motion to solve the problem:
v = u + at
Where:
v = final velocity = 60 \(\frac{m}{s}\)
u = initial velocity = 10 \(\frac{m}{s}\)
a = acceleration = 2 \(\frac{m}{s^2}\)
t = time taken
Substituting the given values in the equation, we get:
60 = 10 + 2t
Solving for t, we get:
t = \(\frac {60-10}{2}\) = 25 s
Therefore, the time taken to attain a speed of 60 m/s is 25 seconds.
Hence, the answer is 25 s.
Answer. A
Approach Solution -3
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